3.565 \(\int \frac {243-162 x+108 x^2-72 x^3+48 x^4-32 x^5}{(729-64 x^6)^2} \, dx\)

Optimal. Leaf size=110 \[ -\frac {\log \left (4 x^2-6 x+9\right )}{17496}-\frac {\log \left (4 x^2+6 x+9\right )}{17496}-\frac {1}{2916 (2 x+3)}-\frac {\log (3-2 x)}{17496}+\frac {5 \log (2 x+3)}{17496}-\frac {\tan ^{-1}\left (\frac {3-4 x}{3 \sqrt {3}}\right )}{8748 \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {4 x+3}{3 \sqrt {3}}\right )}{2916 \sqrt {3}} \]

[Out]

-1/2916/(3+2*x)-1/17496*ln(3-2*x)+5/17496*ln(3+2*x)-1/17496*ln(4*x^2-6*x+9)-1/17496*ln(4*x^2+6*x+9)-1/26244*ar
ctan(1/9*(3-4*x)*3^(1/2))*3^(1/2)+1/8748*arctan(1/9*(3+4*x)*3^(1/2))*3^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.12, antiderivative size = 110, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 6, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {1586, 2074, 634, 618, 204, 628} \[ -\frac {\log \left (4 x^2-6 x+9\right )}{17496}-\frac {\log \left (4 x^2+6 x+9\right )}{17496}-\frac {1}{2916 (2 x+3)}-\frac {\log (3-2 x)}{17496}+\frac {5 \log (2 x+3)}{17496}-\frac {\tan ^{-1}\left (\frac {3-4 x}{3 \sqrt {3}}\right )}{8748 \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {4 x+3}{3 \sqrt {3}}\right )}{2916 \sqrt {3}} \]

Antiderivative was successfully verified.

[In]

Int[(243 - 162*x + 108*x^2 - 72*x^3 + 48*x^4 - 32*x^5)/(729 - 64*x^6)^2,x]

[Out]

-1/(2916*(3 + 2*x)) - ArcTan[(3 - 4*x)/(3*Sqrt[3])]/(8748*Sqrt[3]) + ArcTan[(3 + 4*x)/(3*Sqrt[3])]/(2916*Sqrt[
3]) - Log[3 - 2*x]/17496 + (5*Log[3 + 2*x])/17496 - Log[9 - 6*x + 4*x^2]/17496 - Log[9 + 6*x + 4*x^2]/17496

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 618

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 634

Int[((d_.) + (e_.)*(x_))/((a_) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[(2*c*d - b*e)/(2*c), Int[1/(a +
b*x + c*x^2), x], x] + Dist[e/(2*c), Int[(b + 2*c*x)/(a + b*x + c*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] &
& NeQ[2*c*d - b*e, 0] && NeQ[b^2 - 4*a*c, 0] &&  !NiceSqrtQ[b^2 - 4*a*c]

Rule 1586

Int[(u_.)*(Px_)^(p_.)*(Qx_)^(q_.), x_Symbol] :> Int[u*PolynomialQuotient[Px, Qx, x]^p*Qx^(p + q), x] /; FreeQ[
q, x] && PolyQ[Px, x] && PolyQ[Qx, x] && EqQ[PolynomialRemainder[Px, Qx, x], 0] && IntegerQ[p] && LtQ[p*q, 0]

Rule 2074

Int[(P_)^(p_)*(Q_)^(q_.), x_Symbol] :> With[{PP = Factor[P]}, Int[ExpandIntegrand[PP^p*Q^q, x], x] /;  !SumQ[N
onfreeFactors[PP, x]]] /; FreeQ[q, x] && PolyQ[P, x] && PolyQ[Q, x] && IntegerQ[p] && NeQ[P, x]

Rubi steps

\begin {align*} \int \frac {243-162 x+108 x^2-72 x^3+48 x^4-32 x^5}{\left (729-64 x^6\right )^2} \, dx &=\int \frac {1}{(3+2 x)^2 \left (243-162 x+108 x^2-72 x^3+48 x^4-32 x^5\right )} \, dx\\ &=\int \left (-\frac {1}{8748 (-3+2 x)}+\frac {1}{1458 (3+2 x)^2}+\frac {5}{8748 (3+2 x)}+\frac {3-2 x}{4374 \left (9-6 x+4 x^2\right )}+\frac {3-2 x}{4374 \left (9+6 x+4 x^2\right )}\right ) \, dx\\ &=-\frac {1}{2916 (3+2 x)}-\frac {\log (3-2 x)}{17496}+\frac {5 \log (3+2 x)}{17496}+\frac {\int \frac {3-2 x}{9-6 x+4 x^2} \, dx}{4374}+\frac {\int \frac {3-2 x}{9+6 x+4 x^2} \, dx}{4374}\\ &=-\frac {1}{2916 (3+2 x)}-\frac {\log (3-2 x)}{17496}+\frac {5 \log (3+2 x)}{17496}-\frac {\int \frac {-6+8 x}{9-6 x+4 x^2} \, dx}{17496}-\frac {\int \frac {6+8 x}{9+6 x+4 x^2} \, dx}{17496}+\frac {\int \frac {1}{9-6 x+4 x^2} \, dx}{2916}+\frac {1}{972} \int \frac {1}{9+6 x+4 x^2} \, dx\\ &=-\frac {1}{2916 (3+2 x)}-\frac {\log (3-2 x)}{17496}+\frac {5 \log (3+2 x)}{17496}-\frac {\log \left (9-6 x+4 x^2\right )}{17496}-\frac {\log \left (9+6 x+4 x^2\right )}{17496}-\frac {\operatorname {Subst}\left (\int \frac {1}{-108-x^2} \, dx,x,-6+8 x\right )}{1458}-\frac {1}{486} \operatorname {Subst}\left (\int \frac {1}{-108-x^2} \, dx,x,6+8 x\right )\\ &=-\frac {1}{2916 (3+2 x)}-\frac {\tan ^{-1}\left (\frac {3-4 x}{3 \sqrt {3}}\right )}{8748 \sqrt {3}}+\frac {\tan ^{-1}\left (\frac {3+4 x}{3 \sqrt {3}}\right )}{2916 \sqrt {3}}-\frac {\log (3-2 x)}{17496}+\frac {5 \log (3+2 x)}{17496}-\frac {\log \left (9-6 x+4 x^2\right )}{17496}-\frac {\log \left (9+6 x+4 x^2\right )}{17496}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.11, size = 100, normalized size = 0.91 \[ \frac {-3 \log \left (4 x^2-6 x+9\right )-3 \log \left (4 x^2+6 x+9\right )-\frac {18}{2 x+3}-3 \log (3-2 x)+15 \log (2 x+3)+2 \sqrt {3} \tan ^{-1}\left (\frac {4 x-3}{3 \sqrt {3}}\right )+6 \sqrt {3} \tan ^{-1}\left (\frac {4 x+3}{3 \sqrt {3}}\right )}{52488} \]

Antiderivative was successfully verified.

[In]

Integrate[(243 - 162*x + 108*x^2 - 72*x^3 + 48*x^4 - 32*x^5)/(729 - 64*x^6)^2,x]

[Out]

(-18/(3 + 2*x) + 2*Sqrt[3]*ArcTan[(-3 + 4*x)/(3*Sqrt[3])] + 6*Sqrt[3]*ArcTan[(3 + 4*x)/(3*Sqrt[3])] - 3*Log[3
- 2*x] + 15*Log[3 + 2*x] - 3*Log[9 - 6*x + 4*x^2] - 3*Log[9 + 6*x + 4*x^2])/52488

________________________________________________________________________________________

fricas [A]  time = 0.42, size = 115, normalized size = 1.05 \[ \frac {6 \, \sqrt {3} {\left (2 \, x + 3\right )} \arctan \left (\frac {1}{9} \, \sqrt {3} {\left (4 \, x + 3\right )}\right ) + 2 \, \sqrt {3} {\left (2 \, x + 3\right )} \arctan \left (\frac {1}{9} \, \sqrt {3} {\left (4 \, x - 3\right )}\right ) - 3 \, {\left (2 \, x + 3\right )} \log \left (4 \, x^{2} + 6 \, x + 9\right ) - 3 \, {\left (2 \, x + 3\right )} \log \left (4 \, x^{2} - 6 \, x + 9\right ) + 15 \, {\left (2 \, x + 3\right )} \log \left (2 \, x + 3\right ) - 3 \, {\left (2 \, x + 3\right )} \log \left (2 \, x - 3\right ) - 18}{52488 \, {\left (2 \, x + 3\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-32*x^5+48*x^4-72*x^3+108*x^2-162*x+243)/(-64*x^6+729)^2,x, algorithm="fricas")

[Out]

1/52488*(6*sqrt(3)*(2*x + 3)*arctan(1/9*sqrt(3)*(4*x + 3)) + 2*sqrt(3)*(2*x + 3)*arctan(1/9*sqrt(3)*(4*x - 3))
- 3*(2*x + 3)*log(4*x^2 + 6*x + 9) - 3*(2*x + 3)*log(4*x^2 - 6*x + 9) + 15*(2*x + 3)*log(2*x + 3) - 3*(2*x +
3)*log(2*x - 3) - 18)/(2*x + 3)

________________________________________________________________________________________

giac [A]  time = 0.19, size = 86, normalized size = 0.78 \[ \frac {1}{8748} \, \sqrt {3} \arctan \left (\frac {1}{9} \, \sqrt {3} {\left (4 \, x + 3\right )}\right ) + \frac {1}{26244} \, \sqrt {3} \arctan \left (\frac {1}{9} \, \sqrt {3} {\left (4 \, x - 3\right )}\right ) - \frac {1}{2916 \, {\left (2 \, x + 3\right )}} - \frac {1}{17496} \, \log \left (4 \, x^{2} + 6 \, x + 9\right ) - \frac {1}{17496} \, \log \left (4 \, x^{2} - 6 \, x + 9\right ) + \frac {5}{17496} \, \log \left ({\left | 2 \, x + 3 \right |}\right ) - \frac {1}{17496} \, \log \left ({\left | 2 \, x - 3 \right |}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-32*x^5+48*x^4-72*x^3+108*x^2-162*x+243)/(-64*x^6+729)^2,x, algorithm="giac")

[Out]

1/8748*sqrt(3)*arctan(1/9*sqrt(3)*(4*x + 3)) + 1/26244*sqrt(3)*arctan(1/9*sqrt(3)*(4*x - 3)) - 1/2916/(2*x + 3
) - 1/17496*log(4*x^2 + 6*x + 9) - 1/17496*log(4*x^2 - 6*x + 9) + 5/17496*log(abs(2*x + 3)) - 1/17496*log(abs(
2*x - 3))

________________________________________________________________________________________

maple [A]  time = 0.06, size = 85, normalized size = 0.77 \[ \frac {\sqrt {3}\, \arctan \left (\frac {\left (8 x -6\right ) \sqrt {3}}{18}\right )}{26244}+\frac {\sqrt {3}\, \arctan \left (\frac {\left (8 x +6\right ) \sqrt {3}}{18}\right )}{8748}-\frac {\ln \left (2 x -3\right )}{17496}+\frac {5 \ln \left (2 x +3\right )}{17496}-\frac {\ln \left (4 x^{2}-6 x +9\right )}{17496}-\frac {\ln \left (4 x^{2}+6 x +9\right )}{17496}-\frac {1}{2916 \left (2 x +3\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-32*x^5+48*x^4-72*x^3+108*x^2-162*x+243)/(-64*x^6+729)^2,x)

[Out]

-1/17496*ln(4*x^2-6*x+9)+1/26244*3^(1/2)*arctan(1/18*(8*x-6)*3^(1/2))-1/2916/(2*x+3)+5/17496*ln(2*x+3)-1/17496
*ln(4*x^2+6*x+9)+1/8748*3^(1/2)*arctan(1/18*(8*x+6)*3^(1/2))-1/17496*ln(2*x-3)

________________________________________________________________________________________

maxima [A]  time = 2.98, size = 84, normalized size = 0.76 \[ \frac {1}{8748} \, \sqrt {3} \arctan \left (\frac {1}{9} \, \sqrt {3} {\left (4 \, x + 3\right )}\right ) + \frac {1}{26244} \, \sqrt {3} \arctan \left (\frac {1}{9} \, \sqrt {3} {\left (4 \, x - 3\right )}\right ) - \frac {1}{2916 \, {\left (2 \, x + 3\right )}} - \frac {1}{17496} \, \log \left (4 \, x^{2} + 6 \, x + 9\right ) - \frac {1}{17496} \, \log \left (4 \, x^{2} - 6 \, x + 9\right ) + \frac {5}{17496} \, \log \left (2 \, x + 3\right ) - \frac {1}{17496} \, \log \left (2 \, x - 3\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-32*x^5+48*x^4-72*x^3+108*x^2-162*x+243)/(-64*x^6+729)^2,x, algorithm="maxima")

[Out]

1/8748*sqrt(3)*arctan(1/9*sqrt(3)*(4*x + 3)) + 1/26244*sqrt(3)*arctan(1/9*sqrt(3)*(4*x - 3)) - 1/2916/(2*x + 3
) - 1/17496*log(4*x^2 + 6*x + 9) - 1/17496*log(4*x^2 - 6*x + 9) + 5/17496*log(2*x + 3) - 1/17496*log(2*x - 3)

________________________________________________________________________________________

mupad [B]  time = 5.10, size = 100, normalized size = 0.91 \[ \frac {5\,\ln \left (x+\frac {3}{2}\right )}{17496}-\frac {\ln \left (x-\frac {3}{2}\right )}{17496}-\frac {1}{5832\,\left (x+\frac {3}{2}\right )}-\ln \left (x+\frac {3}{4}-\frac {\sqrt {3}\,3{}\mathrm {i}}{4}\right )\,\left (\frac {1}{17496}+\frac {\sqrt {3}\,1{}\mathrm {i}}{17496}\right )+\ln \left (x+\frac {3}{4}+\frac {\sqrt {3}\,3{}\mathrm {i}}{4}\right )\,\left (-\frac {1}{17496}+\frac {\sqrt {3}\,1{}\mathrm {i}}{17496}\right )-\ln \left (x-\frac {3}{4}-\frac {\sqrt {3}\,3{}\mathrm {i}}{4}\right )\,\left (\frac {1}{17496}+\frac {\sqrt {3}\,1{}\mathrm {i}}{52488}\right )+\ln \left (x-\frac {3}{4}+\frac {\sqrt {3}\,3{}\mathrm {i}}{4}\right )\,\left (-\frac {1}{17496}+\frac {\sqrt {3}\,1{}\mathrm {i}}{52488}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(162*x - 108*x^2 + 72*x^3 - 48*x^4 + 32*x^5 - 243)/(64*x^6 - 729)^2,x)

[Out]

(5*log(x + 3/2))/17496 - log(x - 3/2)/17496 - 1/(5832*(x + 3/2)) - log(x - (3^(1/2)*3i)/4 + 3/4)*((3^(1/2)*1i)
/17496 + 1/17496) + log(x + (3^(1/2)*3i)/4 + 3/4)*((3^(1/2)*1i)/17496 - 1/17496) - log(x - (3^(1/2)*3i)/4 - 3/
4)*((3^(1/2)*1i)/52488 + 1/17496) + log(x + (3^(1/2)*3i)/4 - 3/4)*((3^(1/2)*1i)/52488 - 1/17496)

________________________________________________________________________________________

sympy [A]  time = 0.43, size = 105, normalized size = 0.95 \[ - \frac {\log {\left (x - \frac {3}{2} \right )}}{17496} + \frac {5 \log {\left (x + \frac {3}{2} \right )}}{17496} - \frac {\log {\left (x^{2} - \frac {3 x}{2} + \frac {9}{4} \right )}}{17496} - \frac {\log {\left (x^{2} + \frac {3 x}{2} + \frac {9}{4} \right )}}{17496} + \frac {\sqrt {3} \operatorname {atan}{\left (\frac {4 \sqrt {3} x}{9} - \frac {\sqrt {3}}{3} \right )}}{26244} + \frac {\sqrt {3} \operatorname {atan}{\left (\frac {4 \sqrt {3} x}{9} + \frac {\sqrt {3}}{3} \right )}}{8748} - \frac {1}{5832 x + 8748} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-32*x**5+48*x**4-72*x**3+108*x**2-162*x+243)/(-64*x**6+729)**2,x)

[Out]

-log(x - 3/2)/17496 + 5*log(x + 3/2)/17496 - log(x**2 - 3*x/2 + 9/4)/17496 - log(x**2 + 3*x/2 + 9/4)/17496 + s
qrt(3)*atan(4*sqrt(3)*x/9 - sqrt(3)/3)/26244 + sqrt(3)*atan(4*sqrt(3)*x/9 + sqrt(3)/3)/8748 - 1/(5832*x + 8748
)

________________________________________________________________________________________